Exercice 00-07
Résoudre dans \(\mathbb{R}\):
\(\frac{2x}{x+1}=\frac{2x-1}{x}\)
\(x^2-x-12=0\)
\(2x^2+4x+1=0\)
\(x^4-3x^2+2=0\)
\(3\,|x-4|=10\)
\(\frac{2x}{\sqrt{4-x}}=3\sqrt{4-x}\)
\((x+1)(x+6)=1\)
\(\bigl||x-1|-3\bigr|=1\)
Indications
Forum
Solution
\(S=\{1\}\)
\(S=\{-3,4\}\)
\(S=\{-1\pm \frac{\sqrt{2}}{2}\}\)
\(S=\{\pm 1,\pm\sqrt{2}\}\)
\(S=\{\frac{22}{3},\frac{2}{3}\}\)
\(S=\{\frac{12}{5}\}\)
\(S=\{\frac{-7\pm \sqrt{29}}{2}\}\)
\(S=\{-3,-1,3,5\}\)