Question 12
L'intégrale \(\displaystyle\int_0^1 x\,\sqrt{x^2+1}\,\mathrm{d}x\) vaut
\(\displaystyle 3(2\sqrt{2}-1)\)
\(\displaystyle \frac{\sqrt{2}-1}{2}\)
\(\displaystyle \frac{\sqrt{2}}{2}\)
\(\displaystyle \frac{2\sqrt{2}-1}{3}\)
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